Indigo Domotics

Who has a clever way of handling holidays like today--ones that aren't on a certain date every year. While my dog will only let me sleep so late regardless, I could get another 30 minutes in if my "People are up now so I'm changing the house mode" trigger knew to ignore someone moving around at 7 am on a holiday.

Ways I want to avoid using:

pressing a "Tomorrow is a holiday" button.

manually adding a bunch of date conditions to triggers, unless any trigger working that way is referring to some script magic.

Run this script every night just after midnight. I created the two variables in advance. Creating them at run time is an exercise for the student.

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# indigo.variables[1980497029] # "isHoliday"
# indigo.variables[1479852422] # "whatHoliday"

from datetime import date
import holidays

indigo.variable.updateValue(1980497029, value="False")

us_holidays = holidays.UnitedStates()  # or holidays.US()

if date.today() in us_holidays:
   indigo.variable.updateValue(1980497029, value="True")
   indigo.variable.updateValue(1479852422, us_holidays.get(date.today()))



I don't think holidays is a standard python module is it? You'll probably have to install it first.

jay (support) wrote:

I don't think holidays is a standard python module is it? You'll probably have to install it first.

Could be. It's been a while since I wrote that.

If you don't want to install the holidays module you could make a variable called 'Holiday' or whatever you'd like to call it, then run this script once per day:

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import urllib2
import requests
import simplejson as json
from datetime import datetime
bhVar = indigo.variables[77648381]  #Change this to your Holiday variable ID
thisDay = datetime.today().strftime('%Y-%m-%d')
url = 'http://www.webcal.fi/cal.php?id=435&format=json&start_year=current_year&end_year=current_year&tz=Europe%2FLondon'
resp = requests.get(url=url)
data = json.loads(resp.text)
holDesc = ""
for i in data:
    if i['date'] == thisDay:
        holDesc = i['name']
        break
indigo.variable.updateValue(bhVar, holDesc)


The url shown is for UK but a visit to http://www.webcal.fi/en-GB/other_file_formats.php will enable you to create a url for anywhere in the world. (Be sure to select the json option.) If today is a holiday the variable will be set to its name, otherwise it will be left an empty string. A trigger could be created to do something when the variable is not empty.

racarter wrote:

If you don't want to install the holidays module you could make a variable called 'Holiday' or whatever you'd like to call it, then run this script once per day:
[SNIP]
The url shown is for UK but a visit to http://www.webcal.fi/en-GB/other_file_formats.php will enable you to create a url for anywhere in the world. (Be sure to select the json option.) If today is a holiday the variable will be set to its name, otherwise it will be left an empty string. A trigger could be created to do something when the variable is not empty.

Excellent! I always like solutions that don't require installing Python modules. I found that website somewhat confusing, so to help avoid that here are the steps I took (if they don't redesign the website):

1. Click on Other file formats in the navigation menu to the left
2. Select Holidays from the Calendar popup (or adjust as necessary depending on what you want)
3. Select JSON - JavaScript Object Notation from the File format popup
4. Select your timezone from the Time zone popup
5. Click the Show download URL button
6. Copy the URL shown in red and paste it into the script in place of the url variable in the script (2nd line of my script below)

I simplified the script somewhat - both things that need customization are at the top of the script:

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#### Replace this URL with the one you got from the website above and replace the variable ID with the ID of your variable
url='http://www.webcal.fi/cal.php?id=52&format=json&start_year=current_year&end_year=current_year&tz=America%2FChicago'
variable_id=REPLACE_WITH_VARIABLE_ID
####
import requests
from datetime import date
resp = requests.get(url)
data = resp.json()
holDesc = ""
for i in data:
    if i['date'] == str(date.today()):
        holDesc = i['name']
        break
indigo.variable.updateValue(variable_id, value=holDesc)


I love this, thanks @racarter!

Very cool stuff! Gotta be careful though: Lots of people don't get things like Columbus Day off. Maybe there's a way to make it look at a custom web calendar URL.

Also shame on me for asking such a question on Labor Day, when Jay should be relaxing!

You could always modify the script to ignore specific holidays you don't want flagging...

Just getting around to implementing this.

Ideally I want to run this in the evening, before bedtime to check if its a bank holiday the following day. Is it easy to amend it for 'tomorrow'?

Thanks
Noel

Change:

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    if i['date'] == str(date.today()):

to:

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    if i['date'] == str(date.today() + timedelta(days=1)):

and

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from datetime import date

to:

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from datetime import date, timedelta

Should do it. Not tested at all....

Awesome thank you!


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