Python Arithmetic

So I'm trying to average 2 variables, and store it in a 3rd, but keep striking out.

Here's what I've tired:

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theVar1 = indigo.variables[305363100] #Thermostat
theVar2 = indigo.variables[1728838522] #ExtDevice

theAverage =str(float(theVar1.value) + float(theVar2.value)) / 2 #Average

indigo.variable.updateValue(655793661, ((theAverage)))


And I've tried this with a few different placement and spacings of the "/" and the "2", but doesn't work. I even tried adding some "( )" around part of the 1st line, but that didn't work either

I also tried summing in the 1st equation, and dividing in the 2nd, like this:

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theSum =str(float(theVar1.value) + float(theVar2.value)) #Sum
theAverage =theSum / 2


Again trying different arrangements of the "/" and the "2", but still doesn't work.

My last attempt was this:

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theSum =str(float(theVar1.value) + float(theVar2.value)) #Sum
theAverage =str(float(theSum.value)/2) #Average


But again... nothing.

Any suggestions?

Ugh

So I DO remember this problem and found my original post
https://forums.indigodomo.com/viewtopic.php?f=107&t=12368

While the original solution worked then, its not working with what I've got now.... and I'm thinking that part of my problem now is some of the variables have decimals... and some don't. (int vs float ??)

Not sure if the variable without the decimal will never have it, and vice versa, but will work on that..

What's with all the extra parenthesis in your first code sample?

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theVar1 = indigo.variables[305363100] #Thermostat
theVar2 = indigo.variables[1728838522] #ExtDevice

theAverage = (float(theVar1.value) + float(theVar2.value)) / 2.0      #Average

indigo.variable.updateValue(655793661, str(theAverage))


just trying to help understanding:

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theAverage =str(float(theVar1.value) + float(theVar2.value)) / 2 #Average

divides a string by 2.. like "12345" /2 , which does not make sense



this does 12345/2:

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theAverage =str(    (float(theVar1.value) + float(theVar2.value) )/ 2   )

First of all, THANK YOU for your help. This solved my problem.

I don't pretend to understand all the intricacies of Python, but briefly, I'm assuming this type of equation

(3.5+5.3)/2
is handled differently than this one:
(3+5)/2

And different because of the decimals?

First of all, THANK YOU for your help. This solved my problem.

I don't pretend to understand all the intricacies of Python, but briefly, I'm assuming this type of equation

(3.5+5.3)/2
is handled differently than this one:
(3+5)/2

And different because of the decimals?

The only difference between those is that since the first numbers are floats, the rest of the calculation will be done with floats. So you'll get 8.8/2 = 4.4. The second is all integers, so you get 8/2 = 4.

The key takeaway from this discussion is that if you retrieve variables using the .value property, you get a string. You can specify the data the when you retrieve the value. Starting with the data type you want makes things easier. So a "better" answer to your original code would be:

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theVar1 = indigo.variables[305363100] #Thermostat
theVar2 = indigo.variables[1728838522] #ExtDevice

theAverage = (theVar1.getValue(float) + theVar2.getValue(float)) / 2.0      #Average

indigo.variable.updateValue(655793661, str(theAverage))


This is documented here: https://wiki.indigodomo.com/doku.php?id ... able_class

Or

theVar1 = indigo.variables[305363100].getValue(float)
Etc

Then it’s

(theVar1 + theVar2)/2 which reads easier to me.


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Or

theVar1 = indigo.variables[305363100].getValue(float)
Etc

Then it’s

(theVar1 + theVar2)/2 which reads easier to me.

Agree. But, baby steps....

Agree. But, baby steps....

That's me. I actually can follow the logic... just hope I can remember it next time I need it. I usually "save" my python scripts and a snippet here and there can get me most of where I need to go... nothing very complicated... mostly small things easier done in Python than the GUI.

Thanks again for the help.